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11 June, 06:22

What is the work done when a volume increases from 3 liters

to 5 liters at 6 atm of pressure? (Conversion factor: 1 L atm = 100))

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  1. 11 June, 06:28
    0
    -1215.9J is the work done

    Explanation:

    It is possible to find work done in the change of volume of a gas at constant pressure using:

    W = - P*ΔV

    Where W is work, P is pressure and V is change in volume}

    Replacing:

    W = - 6atm * (5L-3L)

    W = - 12atmL

    As 1atmL = 101,325J, work done in joules is:

    -12atmL * (101.325J / atmL) = - 1215.9J is the work done
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