A chemical company makes pure silver by reacting silver nitrate with zinc. The company needs to make 800 grams of pure silver for a client. They have 300 grams of zinc and 600 grams of silver nitrate. Will they be able to make enough silver to fill the order?

Question

Janitor

Chemistry

19 August, 19:55

A chemical company makes pure silver by reacting silver nitrate with zinc. The company needs to make 800 grams of pure silver for a client. They have 300 grams of zinc and 600 grams of silver nitrate. Will they be able to make enough silver to fill the order?

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Aylin Davenport · Answer 1

The reaction between zinc and silver nitrate is ...

Moles of Zn = m / M = 599 / 65 = 9.2 mol

Moles of AgNO3 = m / M = 1500 / 169 = 8.87 mol

Silver nitrate is reacting completely to give silver. Thus, moles of Silver nitrate is equivalent to silver = 8.87

For mass of silver produced

m / M = 8.87 = m / 107

m = 949.24 g

Hence, the given quantity of reactants are sufficient to produce 800 g of silver as the amount of silver produced is 949.24 g.