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23 July, 19:04

If a 3.30 m sample of a is heated to 500 k, what is the concentration of b at equilibrium?

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  1. 23 July, 19:28
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    (Missing in your question):

    we have the following reaction:

    A (aq) ↔ 2 B (aq)

    and Kc = 7.02 x 10^-6 at 500K

    So at equilibrium,

    Kc = [Products] / [ reactants]

    = [B]^2 / [A]

    we have [A] = 3.3 m and Kc is given = 7.02 x10^-6

    by substitution:

    7.02x10^-6 = [B]^2 / 3.3

    ∴[B]^2 = 2.3 x 10^-5

    ∴[B] = 0.005 m
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