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7 October, 15:59

1) In 1.31 g of a chloride of titanium, there is 0.528 g of titanium. What is the empirical formula of this titanium chloride?

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  1. 7 October, 16:14
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    TiCl2

    Explanation:

    Mass of the chloride of titanium = 1.31 g

    Mass of titanium = 0.528 g

    Therefore mass of chlorine = 1.31-0.528 = 0.782 g

    To determine the empirical formulae of the titanium chloride, divide the mass of each element by its relative atomic mass and divide through by the lowest ratio.

    Ti - 0.528/48 = 0.011, Cl - 0.782/35.5 = 0.022

    Ti - 0.011/0.011, Cl - 0.022/0.011

    Ti - 1, Cl-2

    Hence the required empirical formula is TiCl2
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