How many oxygen atoms are there in 6.00 g of sodium dichromate, na2cr2o7?

Question

Bella Mccoy

Chemistry

25 August, 00:40

How many oxygen atoms are there in 6.00 g of sodium dichromate, na2cr2o7?

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Answers (1)

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Erin · Answer 1

Answer is: there are 9,7·10²² atoms of oxygen.

m (Na₂Cr₂O₇) = 6,00 g.

n (Na₂Cr₂O₇) = m (Na₂Cr₂O₇) : M (Na₂Cr₂O₇).

n (Na₂Cr₂O₇) = 6 g : 262 g/mol.

n (Na₂Cr₂O₇) = 0,023 mol.

n (Na₂Cr₂O₇) : n (O) = 1 : 7.

n (O) = 7 · 0,023 mol.

n (O) = 0,161 mol.

N (O) = 0,161 mol · 6,022·10²³ 1/mol.

N (O) = 9,7·10²².