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16 November, 22:17

How many ml of 0.112 M Pb (NO3) 2 are needed to completely react with 10.0ml of a 0.105 M KI Given Pb (NO3) 2 (aq) + 2KI (aq) = 2KNO3 (aq) ?

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  1. 16 November, 22:42
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    0.105 x 10 / 2 / 0.112 = 4.6875 ml of 0.112M Pb (NO3) 2
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