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3 February, 06:55

If a maximum of 5.60g of a gas at 2.50 atm of pressure dissolves in 3.5-L of water, what will the solubility be if the pressure

changes to 5.00atm?

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Answers (1)
  1. 3 February, 07:10
    0
    According to Henry's law C = k P

    where C = concentration of gas (g/L)

    k : Henry's constant

    P : pressure of gas above the solution

    concentration of gas = 5.6 g / 3.5 L = 1.6 g/L

    From Henry's law:

    C₁ / C₂ = P₁ / P₂

    C₂ = C₁P₂ / P₁ = (1.6 * 5 atm) / 2.5 atm = 3.2 g/L

    so the 3.5 L will contain 11.2 g gas
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