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10 March, 23:23

How much heat is absorbed by a 72g iron skillet when its temperature rises from 80C to 260C?

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  1. 10 March, 23:47
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    The correct answer is 5819.04 J

    The energy (q) required to elevate an object of mass (m) and specific heat capacity (c) by a temperature (T) is given by q = mcΔT.

    Here, m is 72 g, c is 0.449 J/Kg °C, ΔT = 260 - 80 = 180 °C

    Now, putting the values we get,

    q = 72 * 0.449 * 180

    q = 5819.04 J of energy is absorbed by the skillet.
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