How many mL of a 3.5 M sodium hydroxide will be needed to neutralize 15mL of a 4.3 M hydrochloric acid solution?

Step 1 : write a valanced equation ...

NaOH + HCl "NaCl + H2O

Step 2 : find the number of mole of HCl ...

1000 ml ... contains 4.3 mole

15ml ... (4.3:1000) * 15 = ...

Stem 3 : use mole ratio ...

HCl : NaOH

1 : 1

So mole is same as calculated above ...

Step 4:

3.5 mole of NaOH is in 1000ml

(4.3:1000) * 15 mole is in ...

Do the calculation