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29 April, 02:06

How many mL of a 3.5 M sodium hydroxide will be needed to neutralize 15mL of a 4.3 M hydrochloric acid solution?

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  1. 29 April, 02:33
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    Step 1 : write a valanced equation ...

    NaOH + HCl "NaCl + H2O

    Step 2 : find the number of mole of HCl ...

    1000 ml ... contains 4.3 mole

    15ml ... (4.3:1000) * 15 = ...

    Stem 3 : use mole ratio ...

    HCl : NaOH

    1 : 1

    So mole is same as calculated above ...

    Step 4:

    3.5 mole of NaOH is in 1000ml

    (4.3:1000) * 15 mole is in ...

    Do the calculation
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