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26 August, 12:04

What is the molarity of a 10.5 %% by mass glucose (C6H12O6C6H12O6) solution? (The density of the solution is 1.03 g/mLg/mL.) Express your answer to three significant figures.

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  1. 26 August, 12:16
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    Molarity = 54.50 M

    Explanation:

    Molarity is defined as the number of moles of a solute in 1 liter of solution. It has mol/l unit.

    Molar mass of glucose, C6H12O6 = (6*12) + (1*12) + (16*6)

    = 72 + 12 + 96 = 180g/mol

    Density of glucose solution = 1.03g/ml

    Density in g/l = 1.03g/ml * 1ml/10^-3l

    = 1030g/l

    10.5% mass of glucose = 10.5/100 * 180

    = 18.9g/mol

    Molarity = density (g/l) / molar mass (g/mol)

    = 1030/18.9

    = 54.50 M
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