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17 June, 20:09

What is the empirical formula of a compound composed of 3.25% hydrogen (H), 19.36% carbon (C), and 77.39% oxygen (O) by mass?

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  1. 17 June, 20:25
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    CH2O3

    C=19.36/12 = 1.61

    H=3.25/1.008 = 3.22

    O=77.39/16=4.83

    then dived the moles with the smallest mole

    C=1.61/1.61=1

    H=3.22/1.61=2

    O=4.83/1.61=3

    E. F

    CH2O3
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