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30 June, 05:04

A 1.5L intraveneous (IV) solution contains 919 grams glucose (C6H12O6). What is the molarity of this solution?

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  1. 30 June, 05:18
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    3.4 M

    Explanation:

    M = grams/molar mass = ans./volume (L)

    M = 919/180 = ans./1.5
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