Question 8 4 pts What would be the resulting molarity of a solution made by dissolving 31.3 grams of Ca (OH) 2 in enough water to make a 1050-milliliter solution? Show all of the work needed to solve this problem.

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Gary Blake

Chemistry

20 August, 18:22

Question 8 4 pts What would be the resulting molarity of a solution made by dissolving 31.3 grams of Ca (OH) 2 in enough water to make a 1050-milliliter solution? Show all of the work needed to solve this problem.

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Abril Hart · Answer 1

Answer is: molarity of a solution is 0,401 M.

m (Ca (OH) ₂) = 31,3 g.

n (Ca (OH) ₂) = m (Ca (OH) ₂) : M (Ca (OH) ₂).

n (Ca (OH) ₂) = 31,3 g : 74 g/mol.

n (Ca (OH) ₂) = 0,422 mol.

V (solution) = 1050 mL · 0,001 L/mL = 1,050 L.

c (Ca (OH) ₂) = n (Ca (OH) ₂) : V (solution).

c (Ca (OH) ₂) = 0,422 mol : 1,050 L.

n (Ca (OH) ₂) = 0,401 mol/L = 0,401 M.