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9 October, 18:52

How many grams of naoh would react with 507 g fecl2 in the reaction fecl2 + 2naoh fe (oh) 2 (s) + 2nacl?

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  1. 9 October, 19:17
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    Answer: Correct answer is 507g FeCl2 x (1 mol FeCl2 / 126.8 g FeC2) x (1 mol Fe (OH) 2 / 1 mol FeCl2) x (89.8 g Fe (OH) 2 / 1 mol Fe (OH) 2) = 359 g Fe (OH) 2.
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