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15 January, 05:53

A percent composition analysis yields 32.37% sodium, 22.57 sulfur and 45.05% oxygen what is the empirical formula for the compound

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  1. 15 January, 05:57
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    Na₂SO₄

    Explanation:

    Assume that you have 100 g of the compound.

    Then you have 32.37 g Na, 22.57 g S, and 45.05 g O.

    1. Calculate the moles of each element.

    Moles of Na = 32.37 * 1/22.99 = 1.408 mol Na

    Moles of S = 22.57 * 1/32.06 = 0.7040 mol S

    Moles of O = 45.05 * 1/16.00 = 2.816 mol O

    2. Calculate the molar ratios.

    Divide all values by the smallest number.

    Na: 1.408/0.7040 = 2.000

    S: 0.7040/0.7040 = 1

    O: 2.816/0.7040 = 4.000

    3. Determine the empirical formula

    Round off all numbers to the closest integer.

    Na: 2

    S: 1

    O: 4

    The empirical formula is Na₂SO₄.
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