Suppose that a fictitious element, x, has two isotopes: 59x (59.015 amu) and 62x (62.011 amu). the lighter isotope has an abundance of 71.7%. calculate the atomic mass of the element x.

Question

Lucy Odom

Chemistry

13 September, 15:13

Suppose that a fictitious element, x, has two isotopes: 59x (59.015 amu) and 62x (62.011 amu). the lighter isotope has an abundance of 71.7%. calculate the atomic mass of the element x.

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Dalia Marquez · Answer 1

The atomic mass of the element would simply be equal to the sum of the weighted average of each isotope, that is:

atomic mass = 59.015 amu * 0.717 + 62.011 amu * (1 - 0.717)

atomic mass = 59.863 amu