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10 December, 16:59

What will be the pressure of a sample of 48.0 grams of oxygen gas in a glass container of volume 5.2 l at 25 °c?

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  1. 10 December, 17:23
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    We can use the ideal gas equation based on the assumption that O₂ behaves similar to an ideal gas.

    PV = nRT

    P-pressure, V - volume, n - number of moles, R - universal gas constant and T - temperature

    number of O₂ moles - 48.0 g / 32 g/mol = 1.5 mol

    temperature - 25 °C + 273 = 298 K

    substituting the values

    P x 5.2 x 10⁻³ m³ = 1.5 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K

    P = 714.7 kPa
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