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27 December, 04:42

You submerge 100 grams of steel in 200 grams of water. if the steel has an initial temperature of 80°c and the water has an initial temperature of 10°c, what is the final temperature of the system? the specific heat capacity of the steel is 0.15 cal/g•°c

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  1. 27 December, 05:06
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    Q=cmΔT

    Q1 (steel) = Q2 (water)

    c1•m1• (t1-t) = c2•m2• (t-t2)

    628•0.1• (80-t) = 4180•0.2• (t-10)

    5024 - 62.8t = 836t - 8360

    5024 + 8360 = (836+62.8) t

    t = 14.9°
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