Student Z completes his/her calibration step for part 3 and finds an average massA to be 95.237 g ± 0.005 g. However, in his/her calculations, s/he mistakenly uses 85.237 g ± 0.005 g for massA. S/he uses the correct values for massB and masscyl. Will the calculated mass of displaced water be too high, too low, or unchanged? And why?

Question

Guest

Chemistry

1 March, 10:56

Student Z completes his/her calibration step for part 3 and finds an average massA to be 95.237 g ± 0.005 g. However, in his/her calculations, s/he mistakenly uses 85.237 g ± 0.005 g for massA. S/he uses the correct values for massB and masscyl. Will the calculated mass of displaced water be too high, too low, or unchanged? And why?

+3

Answers (2)

Know the Answer?

Amiya Small · Answer 1

It is going to be too low because the mass mistakenly used is lower than the initial.

Coralie · Answer 2

Answer: - Calculated mass of displaced water would be too low.

Explanations: - Mass of water displaced is directly proportional to the mass of the object dropped into water.

Since the average mass of A used for calculations is low than the actual mass, the calculated mass of displaced water would also be low.