Ask Question
17 April, 19:45

How many Liters of fluorine are required to produce 290,8 g of

Eobalt (II) fluoride?

+4
Answers (1)
  1. 17 April, 19:52
    0
    The formula is CoF2

    Mass of one mole = 58.933 + 2 * 18.998 = 59.03827424 gram

    Number of moles = 290 : 59.03827424

    This is approximately 4.912 moles.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How many Liters of fluorine are required to produce 290,8 g of Eobalt (II) fluoride? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers