A 280. L kiln is used for vitrifying ceramics. It is currently operating at 915 ∘C, and the pressure is 1.075 atm. How many moles of air molecules are within the confines of the kiln?

3.0857 moles of air

Explanation:

For this situation, we will use the ideal gas wet: PV = nRT

⇒ with P = pressure (in atm)

⇒ with V = volume (in liter)

⇒ with n = number of moles of gas

⇒ with R = the ideal gas constant = 0.0821 L * atm * K^-1 * mol^-1

⇒ with T = the absolute temperature (in Kelvin)

⇒ 915 °C = 915 + 273.15 K = 1188.15 K

To calculate the number of moles of air we have to distort the formule:

n = (P*V) / (R*T) = (1.075 atm * 280 L) / (0.0821 L * atm * K^-1 * mol^-1 * 1188.15 K)

n = 3.0857 moles of air