A salt solution was found to contain 1.50 g of salt dissolved in 50 mL of water. On evaporation, the recovered salt weighed 1.47 g. What percent of salt was recovered?

A) 20.4%

B) 107%

C) 98%

D) 20.0%

Question

Isaias Conley

Chemistry

6 December, 18:03

A salt solution was found to contain 1.50 g of salt dissolved in 50 mL of water. On evaporation, the recovered salt weighed 1.47 g. What percent of salt was recovered?

A) 20.4%

B) 107%

C) 98%

D) 20.0%

+1

Answers (1)

Know the Answer?

Gordon Avila · Answer 1

C = 98%

Explanation:

Hello,

To determine the percentage of salt recovered, we'll divide the mass of the salt recovered over by the original mass of the salt.

Mass of salt recovered = 1.47g

Initial mass of salt = 1.50g

Percentage of salt recovered = (mass recovered / initial mass of salt) * 100

Percentage of salt recovered = (1.47 / 1.50) * 100

Percentage of salt recovered = 0.98 * 100

Percentage of salt recovered = 98%

The percentage of salt recovered is equal to 98%

A salt solution was found to contain 1.50 g of salt dissolved in 50 mL of water. On evaporation, the recovered salt weighed 1.47 g. What percent of salt was recovered?A) 20.4%B) 107%C) 98%D) 20.0%

A salt solution was found to contain 1.50 g of salt dissolved in 50 mL of water. On evaporation, the recovered salt weighed 1.47 g. What percent of salt was recovered?

A) 20.4%

B) 107%

C) 98%

D) 20.0%