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18 July, 12:39

The K w for water at 0 ∘ C is 0.12 * 10 - 14 M 2. Calculate the pH of a neutral aqueous solution at 0 ∘ C. p H = Is a pH = 7.25 solution acidic, basic, or neutral at 0 ∘ C?

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  1. 18 July, 13:02
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    pH → 7.46

    Explanation:

    We begin with the autoionization of water. This equilibrium reaction is:

    2H₂O ⇄ H₃O⁺ + OH⁻ Kw = 1*10⁻¹⁴ at 25°C

    Kw = [H₃O⁺]. [OH⁻]

    We do not consider [H₂O] in the expression for the constant.

    [H₃O⁺] = [OH⁻] = √1*10⁻¹⁴ → 1*10⁻⁷ M

    Kw depends on the temperature

    0.12*10⁻¹⁴ = [H₃O⁺]. [OH⁻] → [H₃O⁺] = [OH⁻] at 0°C

    √0.12*10⁻¹⁴ = [H₃O⁺] → 3.46*10⁻⁸ M

    - log [H₃O⁺] = pH

    pH = - log 3.46*10⁻⁸ → 7.46
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