A 5.25 L tank holds helium gas at a pressure of 1655 psi. A second 5.25 L tank holds oxygen at a pressure of 440.0 psi. The two gases are mixed in a 5.25 L tank. If the temperature remains the same throughout the process, what is the pressure of the gas mixture in the tank? Assume ideal gas behavior.

Question

Belinda Rosales

Chemistry

5 January, 12:23

A 5.25 L tank holds helium gas at a pressure of 1655 psi. A second 5.25 L tank holds oxygen at a pressure of 440.0 psi. The two gases are mixed in a 5.25 L tank. If the temperature remains the same throughout the process, what is the pressure of the gas mixture in the tank? Assume ideal gas behavior.

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Answers (1)

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Reid Bass · Answer 1

P = 1047.5 psi

Explanation:

Final moles of gas = moles of gas in tank1 + moles of gas in tank2

Use formula:

n = PV/RT

Thus, PV / RT = P1V1 / RT + P2V2 / RT

we can cancel RT thus equation becomes:

PV = P1V1 + P2V2

P x 10.5 = (1655x 5.25) + (440 x 5.25)

P = 1047.5 psi