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Consider a subnet identified as follows: 192.168.31.0/26.

Using the IP ranges from this subnet, what is the IP network mask used by hosts on the subnet?

Use dotted-decimal notation for the answer.

255.255.255.192

255.255.255.224

255.255.255.128

255.255.255.0

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  1. 6 May, 23:23
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    255.255.255.192

    Explanation:

    Given subnet : 192.168.31.0/26

    This implies that there are 26 1-bits in the subnet mask. So the subnet mask is:

    11111111.11111111.11111111.11000000 (26 1's)

    Translating each segment into decimal representation:

    11111111 = 2^7 + 2^6+2^5+2^4+2^3+2^2+2^1+2^0

    = 128+64+32+16+8+4+2+1

    = 255

    11000000 = 2^7 + 2^6

    = 128 + 64

    = 192

    So the overall subnet mask is : 255.255.255.192
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