Ask Question
7 January, 04:30

The mass fractions of total ferrite and total cementite in an iron-carbon alloy are 0.91 and 0.09, respectively. Is this a hypoeutectoid or hypereutectoid alloy? Why?

+4
Answers (1)
  1. 7 January, 04:43
    0
    hypoeutectoid

    Explanation:

    ferrite: pure form of iron

    cementite: It is iron carbide with 93.3% iron and 6.67% carbon

    hypoeutectoid: Eutectoid steel with carbon fraction less than 0.8%

    hypereutectoid: Eutectoid Steel with carbon content more than 0.8%

    For the mentioned iron-carbide alloy,

    % of carbon in iron-carbide alloy = percentage of cementite * percentage of carbon in cementite

    % of carbon in iron-carbide alloy = 0.09 * 0.0667

    = 0.6%

    so the alloy is hypoeutectoid
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The mass fractions of total ferrite and total cementite in an iron-carbon alloy are 0.91 and 0.09, respectively. Is this a hypoeutectoid or ...” in 📗 Engineering if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers