If a motor driven by PWM using half-bridge operation has a speed of 1,426 rpm at a duty cycle of 100% (full forward), what will its speed be at a duty cycle of 47%

Question

Cash Drake

Engineering

8 February, 19:18

If a motor driven by PWM using half-bridge operation has a speed of 1,426 rpm at a duty cycle of 100% (full forward), what will its speed be at a duty cycle of 47%

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Answers (1)

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Kamryn Pollard · Answer 1

Speed of the motor proportional to duty ratio.

Since duty ratio is proportional to width of the pulse.

So with 61% duty ratio the speed is given by

N = D * Speed of motor with 100% duty ratio

N = 0.47 * 1426

= 670.22 rpm