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6 January, 01:47

The only solution of the equation x^2 + bc+16=0 is x=4 why is the value of b

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  1. 6 January, 01:52
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    Do you mean bc as the middle term, or is it bx?

    If it has only a solution of x = 4, then you must have

    (x - 4) (x - 4) = 0

    x^2 - 8x + 16 = 0

    -8x = bx

    b = - 8
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