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3 December, 11:38

The ages of bob's children are 3 consecutive integers. the sum of the first integer, the second integer and 2 times the third integer is 25. find the ages

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  1. 3 December, 11:42
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    Let x be the age of the first child, then x+1 and x+2 will be the ages of the second and third child respectively

    x+x+1+2 (x+2) = 25

    4x+5=25

    4x=20

    x=5

    So the ages are 5,6,7
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