What are they intercepts of y=2x^2-3x-20 a) x=-5 and 2 b) x=5 and - 2 c) x=-2.5 and 4 d) x=2.5 and - 4

Question

Adelaide Byrd

Mathematics

12 April, 00:58

What are they intercepts of y=2x^2-3x-20 a) x=-5 and 2 b) x=5 and - 2 c) x=-2.5 and 4 d) x=2.5 and - 4

+5

Answers (1)

Know the Answer?

Aarav Juarez · Answer 1

X-intercept: Set y = 0 and find x. Then 2x^2-3x-20 = 0. You must find the roots; there will be two real, unequal roots. The x-intercepts will look like (a, 0) and (b, 0), where a and be are your two real, unequal roots.

y-intercept: set x=0. Then 2 (0) ^2 - 3 (0) - 20 = - 20. The y-int. is (0,-20).