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17 January, 13:14

Suppose that h (x+1) = h (x) + h (x-1) and that h (0) = 3 and h (1) = 12. Find h (2), h (3) and h (-1)

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  1. 17 January, 13:25
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    For x=1

    h (2) = h (1) + h (0)

    h (2) = 12+3

    h (2) = 15

    for x=2

    h (3) = h (2) + h (1)

    h (3) = 15+12

    h (3) = 27

    for x=0

    h (1) = h (0) + h (-1)

    12=3+h (-1)

    h (-1) = 12-3

    h (-1) = 9
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