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Elisha Jacobs
Mathematics
29 January, 12:58
How do you expand (x-4) ^2?
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Kerry
29 January, 13:01
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(x - 4) ^2 = x^2 - 8*x + 16
Step-by-step explanation:
(a - b) ^2 = a^2 - 2*a*b + b^2
(x - 4) ^2 = x^2 - 2*x*4 + 4^2 = x^2 - 8*x + 16
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Quinton Berry
29 January, 13:02
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Answer: x^2 - 8x + 16
Let y = x-4
(x-4) ^2 = (x-4) * (x-4)
(x-4) ^2 = y * (x-4) ... replace one copy of (x-4) with y
(x-4) ^2 = x*y - 4*y ... distribute
(x-4) ^2 = x * (y) - 4 (y)
(x-4) ^2 = x (x - 4) - 4 (x - 4) ... replace y with x-4
(x-4) ^2 = x^2-4x-4x+16 ... distribute
(x-4) ^2 = x^2 - 8x + 16
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