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Anne Proctor
Mathematics
30 December, 04:48
solve the trigonometric equation
3-3cosx=2 sin^2 x
+4
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Avery Madden
30 December, 04:51
0
= 3 - 3cos x - 2 (1 - cos^2 x)
= 2cos^2 x - 3cos x + 1
= (cos x - 1) (cosx - 1/2)
now cos x = 1 or cos x = 1/2
draw a graph we get = + ve values
hence ... 0,180,360 and 60,240, degrees in range x<2pi
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