Ask Question
30 December, 04:48

solve the trigonometric equation

3-3cosx=2 sin^2 x

+4
Answers (1)
  1. 30 December, 04:51
    0
    = 3 - 3cos x - 2 (1 - cos^2 x)

    = 2cos^2 x - 3cos x + 1

    = (cos x - 1) (cosx - 1/2)

    now cos x = 1 or cos x = 1/2

    draw a graph we get = + ve values

    hence ... 0,180,360 and 60,240, degrees in range x<2pi
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “solve the trigonometric equation 3-3cosx=2 sin^2 x ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers