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Brooks Valdez
Mathematics
3 June, 11:43
Is there a solution to 2x^2+7x-4=0?
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Lilian Mclean
3 June, 11:50
0
Ax^2+bx+c=0
always answer is:
-b + (b^2-4ac) / 2a
and
-b - (b^2-4ac) / 2a
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Leonard Mckenzie
3 June, 12:12
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x = - 8 x = 1
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