A diver begins on a platform 10 meters above the surface of the water. The diver's height is given by the equation h (t) = - 4.9t^2 + 6.5t + 10, where t is the time in seconds after the diver jumps.

How many real solutions does the equation have when the diver's height is 3 m? What are they? Round to the hundredths place.

Question

Jade Acosta

Mathematics

20 August, 02:03

A diver begins on a platform 10 meters above the surface of the water. The diver's height is given by the equation h (t) = - 4.9t^2 + 6.5t + 10, where t is the time in seconds after the diver jumps.

How many real solutions does the equation have when the diver's height is 3 m? What are they? Round to the hundredths place.

+1

Answers (1)

Know the Answer?

Reynaldo Carey · Answer 1

For this case we have the following equation:

h (t) = - 4.9t ^ 2 + 6.5t + 10

Substituting the height we have:

3 = - 4.9t ^ 2 + 6.5t + 10

Rewriting:

-4.9t ^ 2 + 6.5t + 10 - 3 = 0

-4.9t ^ 2 + 6.5t + 7 = 0

Which solutions are:

t1 = - 0.70

t2 = 2.03

Answer:

the equation has 2 real solutions.

they are:

t1 = - 0.70

t2 = 2.03