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17 April, 17:52

Find the zeros of the function

f (x) = x^3-7x^2+6x

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  1. 17 April, 17:54
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    f (x) = x^3-7x^2+6x

    The zeros of the function

    x^3-7x^2+6x = 0

    x (x^2 - 7x + 6) = 0

    x (x - 6) (x - 1) = 0

    x = 0

    x - 6 = 0; x = 6

    x - 1 = 0; x = 1

    Answer

    x = 0, 1, 6
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