Find two condecutive odd integers such that the smaller one is twelve more than one-third the larger

Question

Deshawn Wilson

Mathematics

1 March, 01:04

Find two condecutive odd integers such that the smaller one is twelve more than one-third the larger

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Answers (1)

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Irene Mata · Answer 1

Let be x and x + 2 two consecutive odd integers;

You have the equation : x = 12 + (x + 2) / 3;

(3x) / 3 = 36 / 3 + (x + 2) / 3;

(3x) / 3 = (38 + x) / 3;

3x = 38 + x;

2x = 38;

x = 19;

The numbers are 19 and 21.