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Tabetha
Mathematics
27 December, 00:06
What does 7^x=21 in a logarithmic equation
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Shyla Larson
27 December, 00:29
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Loga x=n ⇔ a^n=x
log₇ 21=x
x=log ₇ 21
x=ln 21 / ln7=1.564575034 ...
Answer: x=log₇ 21
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