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27 December, 00:06

What does 7^x=21 in a logarithmic equation

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  1. 27 December, 00:29
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    Loga x=n ⇔ a^n=x

    log₇ 21=x

    x=log ₇ 21

    x=ln 21 / ln7=1.564575034 ...

    Answer: x=log₇ 21
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