Ask Question
3 April, 18:53

The area of a rectangle is 66 ft2, and the length of the rectangle is 1 ft more than twice the width. Find the dimensions of the rectangle.

+2
Answers (1)
  1. 3 April, 19:03
    0
    This is probably way overcomplicated but i cant remember how to do it

    w = n

    l = 2n+1

    w*l = 66

    n (2n+1) = 66

    2n^2 + n = 66

    2n^2 + n - 66 = 0

    using quadratic equation

    n = 11/2

    width = 11/2 = 5.5

    length = 11 + 1 = 12
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The area of a rectangle is 66 ft2, and the length of the rectangle is 1 ft more than twice the width. Find the dimensions of the rectangle. ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers