The result of dividing (x3 + x2 - 22x - 40) by (x - 5) is x2 + 6x + 8. Select all of the factor (s) of x2 + 6x + 8.

The ~correct~ answer would be (x + 4) and (x + 2) so the second and fourth one

We are asked in the problem to determine the factors of x2 + 6x + 8 as a quotient of x3 + x2 - 22x - 40 and (x - 5). In this case, we can use factoring method to determine the roots of x2 + 6x + 8.

let y = 0

y = x2 + 6x + 8 = 0

(x+2) (x+4) = 0

roots: x = - 2; x = - 4