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Find three consecutive integer whose sum is 117

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  1. 24 June, 04:21
    0
    117/3 = 39

    39 + 39 + 39 = 177

    They must be consecutive.

    The integers are 37, 39, and 41.
  2. 24 June, 04:25
    0
    X + (x+1) + (x+2) = 117

    3x+3=117

    3x=114

    x=48

    Final answers: 38, 39, 40
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