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6 May, 06:46

Given that f (x) = x² + 5x, evaluate f (-2).

-6

-14

7

+3
Answers (1)
  1. 6 May, 07:10
    0
    F (x) = x^2 + 5x ... evaluate f (-2) ... so sub in - 2 everywhere there is an x

    f (-2) = - 2^2 + 5 (-2)

    f (-2) = 4 - 10

    f (-2) = - 6 <==
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