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21 April, 11:24

The length of time it takes passengers to get through the security checks at a large urban airport follows a normal distribution with a mean of 20.6 minutes and a standard deviation of 8.4 minutes. What is the probability that a passenger will take longer than 40 minutes to get through the security check?

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  1. 21 April, 13:18
    You would take your statistic of 40 and subtract the mean and divide by the standard deviation so (40-20.6) / 8.4=2.31 (rounded) this is your z score. you need to look this up in the table to find your probability. you would want to know the tail above 40 so it would be. 01044
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