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6 February, 21:47

37. Which is an equation for the circle with a center

at (-2, 3) and a radius of 3?

A. x2 + y2 + 4x - 6y+22=0

B. 2x2 + 2y2 + 3x - 3y+4=0

C. x2 + y2 + 4x - 6y+4=0

D. 3x2 + 3y2 + 4x - 6y+4=0

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Answers (1)
  1. 6 February, 22:02
    0
    C

    Step-by-step explanation:

    (x+2) ² + (y-3) ² = 3²

    x² + y² + 4x - 6y + 4 + 9 - 9 = 0

    x² + y² + 4x - 6y + 4 = 0
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