Ask Question
22 May, 16:01

A test consists of 20 problems and students are told to answer any 15 of these questions. In how many different ways can they choose the 15 questions?

+5
Answers (2)
  1. 22 May, 16:09
    0
    Since order is not important, we are looking for unique combinations. For this type of problem you use the "n choose k" equation.

    n! / (k! (n-k) !), where n=total amount of choices, k=number of choices made.

    In this case:

    20! / (15! (20-15) !)

    20! / (15!*5!)

    15504
  2. 22 May, 16:29
    0
    1 - 15

    2 - 17

    3 - 18

    4 - 19

    5 - 20
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A test consists of 20 problems and students are told to answer any 15 of these questions. In how many different ways can they choose the 15 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers