A model rocket is launched from ground level. Its height, h meters above the ground, is a function of time t seconds after launch and is given by the equation h=-4.9t^2+68.6t What would be the

maximum height, to the nearest meter, attained by the model?

240 m to nearest meter.

Step-by-step explanation:

h = - 4.9t^2 + 68.6t

We need to convert this to vertex form to find the maximum value of h:

h = - 4.9 (t^2 - 14t)

h = - 4.9[ (t - 7) ^2 - 49]

h = - 4.9 (t - 7) ^2 + 240.1

So maximum height is when t = 7 and it's 240.1 meters.