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If x=at^3 and y=bt^2 then find dy/dx

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  1. 9 May, 21:26
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    Dy/dx = (dy/dt) / (dx/dt)

    dy/dt = 2bt

    dx/dt = 3at^2

    therefore dy/dx = 2bt/3at^2

    dy/dx = 2b/3at
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