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24 August, 18:55

A father is 7 times as old as his son. The sum of their ages is 56 years. What is the age of each?

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Answers (2)
  1. 24 August, 19:02
    0
    Answer: The father is 49 years old and the son is 7 years old

    Step-by-step explanation: Let the son's age be y and if the father is seven times as old as his son, then the father's age would be expressed as 7 times y, or 7y.

    Also the sum of their ages is 56 years which means son's age plus father's age equals 56. That is;

    y + 7y = 56

    8y = 56

    Divide both sides of the equation by 8

    y = 7

    Therefore if y is 7, then

    7y = 7 (7)

    7y = 49

    Therefore it means the father is 49 years old while the son is 7 years old
  2. 24 August, 19:17
    0
    The son is 7, the father is 49.

    Step-by-step explanation:

    This was a guess-and-check process. I knew this answer was correct because 7*7=49, and 49+7=56.
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