Brian tied a 136-foot rope around the perimeter of his rectangular house. He knows that the length of the house is 10 feet less than twice the width. Find the dimensions of Brian's house.

length 42 cm and width 26 cm

Step-by-step explanation:

Given

Since Brian tied 136 foot rope around the perimeter, hence perimeter of house is 136 foot.

Given that shape of house is rectangular.

formula to calculate perimeter of rectangle can be used which is 2 * (L+B)

where L is length of rectangle and B width of rectangle

Let the L and B be length of rectangular side of house

According to question

length of house is 10 feet less than twice the width of house

mathematically it can be represented as

L = 2*B - 10 - -->eq. 1

Perimeter of house = 136 feet

using formula of Perimeter of rectangle

136 = 2 * (L+B)

substituting the value of length in terms of width from eq. 1 in formula of perimeter

=> 136/2 = 2*B - 10 + B (2*B + B = 3B)

=> 68 = 3*B - 10

=> 78 = 3*B

B = 78/3 = 26

Therefore B which is width = 26 CM

length = 2*B - 10 = 26*2 - 10 = 52-10=42

length of house = 42 cm

Hence dimension of Brian's house is length 42 cm and width 26 cm