Simplify this radical. Which ordered pair makes both inequalities true? y > - 3x + 3 y > 2x - 2 (1,0) (-1,1) (2,2) (0,3)

First, split this inequality then try each answer.

y>-3x+3y>2x-2

split this into two and simplify each,

y > - 3x + 3y - 3x+3y > 2x - 2

y - 3y > - 3x 3y>2x+3x - 2

-2y > - 3x 3y>5x - 2

2y<3x

Substituting all the 3 ordered pairs, none of them makes the inequalities true.